oracle SQL递归

pid  id
  a   b   
  a   c     
  a   e   
  b   b1   
  b   b2   
  c   c1   
  e   e1   
  e   e3   
  d   d1   
    
指定pid=a，选出   
  a   b   
  a   c     
  a   e   
  b   b1   
  b   b2   
  c   c1   
  e   e1   
  e   e3  
SQL语句：select   parent,child   from   test   start   with   pid='a'   
connect   by   prior   id=pid

1、表机构
SQL> desc comm_org_subjection
Name                                      Null?    Type
----------------------------------------- -------- ----------------------------
ORG_SUBJECTION_ID                         NOT NULL VARCHAR2(32)    子键
ORG_ID                                    NOT NULL VARCHAR2(32)
FATHER_ORG_ID                             NOT NULL VARCHAR2(32)         父键
LOCKED_IF                                 NOT NULL VARCHAR2(1)
START_DATE                                NOT NULL DATE
END_DATE                                           DATE
EDITION_NAMEPLATE                                  NUMBER(8)
CODE_AFFORD_IF                                     VARCHAR2(1)
CODE_AFFORD_ORG_ID                        NOT NULL VARCHAR2(32)
CODING_SHOW_ID                                     NUMBER(8)
BSFLAG                                             VARCHAR2(1)
MODIFI_DATE                                        DATE
CREATOR_ID                                         VARCHAR2(32)
CREATE_DATE                                        DATE
CREATOR                                            VARCHAR2(35)

2、递归查找父结点 org_id为C6000000000001下的所有子结点:
select * from comm_org_subjection a
start with a.org_id='C6000000000001'
connect by prior a.org_subjection_id=a.father_org_id

3、递归查找子结点 org_id为C6000000000001下的所有父结点:
select org_id from comm_org_subjection a
start with a.org_id='C6000000000001'
connect by prior a.father_org_id=a.org_subjection_id